UVALive 6179 Windmill Animation 规律题 - 九野的博客 - CSDN博客

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#include
#include
#include
#include
#include
#include
using namespace std;
const double Pi = acos(-1.0);
typedef long long ll;
const int N = 100;
int n, k, now, pre;
struct node{
	double x, y, ans;
}a[N];
double jiao;
double work(double x){
	while(x<0)x+=Pi;
	while(x>Pi)x-=Pi;
	return x;
}
double dis(node i, node j, node k){
	j.x -= i.x; j.y -= i.y;
	k.x -= i.x; k.y -= i.y;
	return acos((j.x*k.x+j.y*k.y)/(sqrt(j.x*j.x + j.y*j.y) * sqrt(k.x*k.x + k.y*k.y)));
}
bool xmul(node i, node j, node k){
	j.x -= i.x; j.y -= i.y;
	k.x -= i.x; k.y -= i.y;
	return (j.x*k.y - j.y*k.x) > 0;
}
void solve(){
	int ans = -1; double hehe;
	node X, Y;
	X.x = a[now].x + 1000.0*cos(jiao);
	Y.x = a[now].x + 1000.0*cos(jiao+Pi);
	X.y = a[now].y + 1000.0*sin(jiao);
	Y.y = a[now].y + 1000.0*sin(jiao+Pi);
	for(int i = 1; i <= n; i++) if(i!=now){
        if(i==pre) {a[i].ans = Pi;}
        else {
       //     double a1 = dis(a[now],  X, a[i]), a2 = dis(a[now], Y, a[i]);		printf("a[%d] : %.6f %.6f\n", i, a1, a2);
            if(xmul(a[now], X, a[i]))
                a[i].ans = work(dis(a[now],  X, a[i]));
            else
                a[i].ans = work(dis(a[now],  Y, a[i]));
        }
		if(ans == -1 || hehe > a[i].ans){
			ans = i;
			hehe = a[i].ans;
		}
	}
	jiao += a[ans].ans;
	jiao = work(jiao);
	pre = now;
	now = ans;
}
int main(){
	int T, Cas;scanf("%d",&T);
	while(T--){
		scanf("%d %d %d %d %lf",&Cas,&n,&k,&now,&jiao);
		jiao = jiao/180.0*Pi;
		for(int i = 1; i <= n; i++)
		{
			int num; double x,y;
			scanf("%d %lf %lf",&num,&x,&y);
			a[num].x = x;
			a[num].y = y;
		}
		pre = -1;
		printf("%d",Cas);
		while(k--){

			solve();
			printf(" %d", now);
		}
		puts("");
	}
	return 0;
}
/*


*/






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